Solving a hard equation

1. Nov 15, 2004

mathrocks

I have the given equation: (6^x+6^-x)/6 = 2. How do you solve this?

2. Nov 15, 2004

arildno

1. Multiply your equation with $$6^{x}$$
2. You have now a quadratic equation in the unknown $$y=6^{x}$$
As an alternative, use the identity:
$$Cosh(t)=\frac{e^{t}+e^{-t}}{2}$$

Last edited: Nov 15, 2004