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Solving a hard equation

  1. Nov 15, 2004 #1
    I have the given equation: (6^x+6^-x)/6 = 2. How do you solve this?
     
  2. jcsd
  3. Nov 15, 2004 #2

    arildno

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    1. Multiply your equation with [tex]6^{x}[/tex]
    2. You have now a quadratic equation in the unknown [tex]y=6^{x}[/tex]
    As an alternative, use the identity:
    [tex]Cosh(t)=\frac{e^{t}+e^{-t}}{2}[/tex]
     
    Last edited: Nov 15, 2004
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