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**1. Homework Statement**

http://img205.imageshack.us/img205/2327/nummer1.jpg [Broken]

**2. Homework Equations**

If you use ti-89 titanium, you write log with base(b) (c=number) as log(c,b) fx; the log of 3

^{x}in base 5 is writen log(3

^{x},5) (log

_{5}(3

^{x}))took me forever to figure out

**3. The Attempt at a Solution**

I filled out about 5 handwriten papers with attempts, all wich failled. dont force me to write all my attempts since i find this to be very tedius.

simplified, the equation is;

10*5

^{x}=3*5

^{-x}+1

i put log

_{5}on each side geting:

log

_{5}(5

^{x}+3)-x=x+log

_{5}(10)

then moving it about a bit i get:

2x-log

_{5}(5

^{x}+3)=log

_{5}(10)

But here i get stuck...

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