- 3

- 0

## Main Question or Discussion Point

Can't remember how to do this (trying to solve for D):

x = b/D + a*log(D)

Any takers? Or is this impossible?

x = b/D + a*log(D)

Any takers? Or is this impossible?

- Thread starter natgbz
- Start date

- 3

- 0

Can't remember how to do this (trying to solve for D):

x = b/D + a*log(D)

Any takers? Or is this impossible?

x = b/D + a*log(D)

Any takers? Or is this impossible?

symbolipoint

Homework Helper

Education Advisor

Gold Member

- 5,732

- 979

Multiplicative inverse of 'a';

Not sure if the rest is impossible. I'm stuck, since D is the input of the logarithm function and it occurs as a factor too. Am I forgetting something simple, or is this beyond "intermediate" level algebra?

- 3

- 0

Multiplicative inverse of 'a';

Not sure if the rest is impossible. I'm stuck, since D is the input of the logarithm function and it occurs as a factor too. Am I forgetting something simple, or is this beyond "intermediate" level algebra?

Maybe I can simplify the problem here:

a, b, and c are real numbers, D is greater than zero

c = b/D + a*log(D)

how does one solve for D?

HallsofIvy

Science Advisor

Homework Helper

- 41,738

- 898

- 3

- 0

How bout a Taylor Series expansion?

- Last Post

- Replies
- 10

- Views
- 3K

- Last Post

- Replies
- 7

- Views
- 2K

- Last Post

- Replies
- 2

- Views
- 1K

- Replies
- 4

- Views
- 2K

- Replies
- 10

- Views
- 13K

- Replies
- 7

- Views
- 3K

- Replies
- 13

- Views
- 834

- Replies
- 11

- Views
- 2K