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x = b/D + a*log(D)

Any takers? Or is this impossible?

- Thread starter natgbz
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- #1

- 3

- 0

x = b/D + a*log(D)

Any takers? Or is this impossible?

- #2

symbolipoint

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Multiplicative inverse of 'a';

Not sure if the rest is impossible. I'm stuck, since D is the input of the logarithm function and it occurs as a factor too. Am I forgetting something simple, or is this beyond "intermediate" level algebra?

- #3

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Multiplicative inverse of 'a';

Not sure if the rest is impossible. I'm stuck, since D is the input of the logarithm function and it occurs as a factor too. Am I forgetting something simple, or is this beyond "intermediate" level algebra?

Maybe I can simplify the problem here:

a, b, and c are real numbers, D is greater than zero

c = b/D + a*log(D)

how does one solve for D?

- #4

HallsofIvy

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- #5

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How bout a Taylor Series expansion?

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