- #1
natgbz
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Can't remember how to do this (trying to solve for D):
x = b/D + a*log(D)
Any takers? Or is this impossible?
x = b/D + a*log(D)
Any takers? Or is this impossible?
symbolipoint said:Additive inverse of b/D;
Multiplicative inverse of 'a';
Not sure if the rest is impossible. I'm stuck, since D is the input of the logarithm function and it occurs as a factor too. Am I forgetting something simple, or is this beyond "intermediate" level algebra?
HallsofIvy said:One doesn't. Not in terms of elementary functions anyway. It might be possible to solve it in terms of the "Lambert W function".
A logarithm is a mathematical function that is the inverse of the exponential function. It is written in the form logb(x) = y, where b is the base, x is the argument, and y is the solution.
Solving logarithms is important in many fields, such as mathematics, science, economics, and engineering. It is used to solve equations and model real-world situations, as well as to simplify complex calculations.
To solve a logarithm, you can use the logarithm properties and algebraic techniques to rewrite it in a simpler form. Then you can use the inverse operation, exponentiation, to find the solution. It is also helpful to review the rules and formulas for solving logarithms.
If you can't remember how to solve a logarithm, you can try using a logarithm calculator or looking up examples and explanations online. You can also seek help from a tutor or consult a textbook or other resources.
Yes, there are several tips for solving logarithms more efficiently. First, it is important to review and understand the properties and rules of logarithms. It can also be helpful to simplify the logarithm as much as possible before attempting to solve it. Additionally, practicing and solving more logarithm problems can improve your skills and speed.