Solving a second order ODE using reduction of order

  • #1
Bonnie
18
1

Homework Statement


Hi there, I have an assignment which involves using reduction of order to solve for a second solution to an ode (the one attached). However this is a method I am new to, and though I have tried several times, I'm somehow getting something wrong because the LHS and RHS are not matching up, that is, when I substitue in the solution I have found, the RHS does not equal zero as it should.

Homework Equations




The Attempt at a Solution


I have attached my working (Sides 1 and 2), if anyone could point out what I'm doing wrong it would be greatly appreciated, this is driving me nuts!
 

Attachments

  • Question.JPG
    Question.JPG
    8.4 KB · Views: 320
  • s1.jpg
    s1.jpg
    54.4 KB · Views: 356
  • s2.jpg
    s2.jpg
    62.3 KB · Views: 338

Answers and Replies

  • #2
Delta2
Homework Helper
Insights Author
Gold Member
5,695
2,473
According to wolfram your general solution is correct.

You do a blunt mistake in the check, you put ##y'=-\frac 1 2 t^{-\frac 1 2}##, the minus in front is not needed. It is clear that ##y'=\frac{1}{2} t^{-\frac 1 2}## for ##y=t^{\frac 1 2}##
 
  • #3
Bonnie
18
1
According to wolfram your general solution is correct.

You do a blunt mistake in the check, you put ##y'=-\frac 1 2 t^{-\frac 1 2}##, the minus in front is not needed. It is clear that ##y'=\frac{1}{2} t^{-\frac 1 2}## for ##y=t^{\frac 1 2}##
Oh, that was dumb. Thank you!
 

Suggested for: Solving a second order ODE using reduction of order

Replies
1
Views
526
Replies
5
Views
509
Replies
8
Views
232
Replies
33
Views
2K
Replies
17
Views
524
  • Last Post
Replies
4
Views
270
Replies
5
Views
342
  • Last Post
Replies
33
Views
2K
Replies
4
Views
643
Replies
12
Views
732
Top