# Solving a Spring Question: Find Block Height to 2 Sig Figs

• random__
In summary, the conversation discusses a physics question involving a spring (k = 600 N/m) and a 4.0 kg block. The question asks how far above the point of release the block will rise. Two different methods are used to solve the problem, but the online tutorial still says the answer is wrong. The conversation goes on to discuss another way to approach the problem and a potential error in interpreting the question. Finally, the correct answer is given as 6.54 cm, which ignores any negative signs or adding to the initial displacement.
random__
Hey I've worked on this question for so long and can't get the right answer (I don't know what it is though).

A spring (k = 600 N/m) is placed in a vertical position with its lower end supported by a horizontal surface. The upper end is depressed 20 cm, and a 4.0 kg block is placed on the depressed spring. The system is then released from rest. How far above the point of release will the block rise?

I've gotten the answer of 27cm by two different methods but my online tutorial still says it's wrong. Firstly, I used 1/2*k*x^2 where x=0.2 to get the total mechanical energy for the system (12J). At the highest point, the velocity of the block will be 0, therefore its kinetic energy will be 0. Therefore, the energy in the spring + the gravitational potential energy will = 12J. Using this i got x=7cm which means the block rose 27cm.

I then used the equation that Fnet=Fspring-Fweight
ma=-600x-mg
dv/dt=-150x-9.8
v=-75x^2-9.8x+C
subbed in @ x=-0.2, v=0
:. v=-75x^2-9.8x+1.04

Using this i got v=0 at -20cm and 7cm, which gives the same answer as above. What am I doing wrong?
Thanks

One more way to do this problem is to find the equilibrium position of the mass on the spring, and find the initial position relative to that. You know that if the equilibrium position is above the starting point, the initial displacement from equilibrium will be the amplitude of the motion, and the mass will move twice that far. I think you will still get your answer.

Yes, I agree with OlderDan. It seems you are doing it much more complicated than it has to be. The system consisting of a the spring and mass will reach equilibrium when forces are equal. That means that the weight of the mass will be equal to the force of the spring pushing upwards. If you have the mass of the block, then you have the weight, then solve the spring force equation for x. Subtract from your intial starting point to get the rise.

I tried doing that too. Is this what you mean
-kx = mg
x=mg/-k
using this i get x=-7cm, which would mean the block moves up 13cm right? This was my initial answer to the problem but that was wrong too.

random__ said:
I tried doing that too. Is this what you mean
-kx = mg
x=mg/-k
using this i get x=-7cm, which would mean the block moves up 13cm right? This was my initial answer to the problem but that was wrong too.

Yes. -7cm means you are starting 13cm below and you will go 13 cm above so you move 26 cm. It's the same answer you keep getting within the round off. Either you have interpreted the problem wrong, or the answer you have been given is wrong. It happens now and then.

What I"ve put above is the question word for word from the online tutorial. I don't think the correct answer according to the online tut would be wrong as this is an assessment item. Is there any other way this question can be interpretted?

random__ said:
What I"ve put above is the question word for word from the online tutorial. I don't think the correct answer according to the online tut would be wrong as this is an assessment item. Is there any other way this question can be interpretted?

Yes there is. Sorry for not catching it sooner. The 4 kg mass is PLACED on top of the spring, not attached to the spring, as I had assumed when thinking about this earlier. That makes a whole lot of difference.

can you please elaborate on how this would affect the calculations because I don't see it? thanks

Is there an answer that is around 7? To two significant figures, I came up with 6.54 cm. It asked how far above the initial point will the block rise, so you can ignore any negative signs or adding to initial value of displacement

I would think if 6.54cm doesn't work, then somethings wrong.

random__ said:
can you please elaborate on how this would affect the calculations because I don't see it? thanks
I'm sure they want you to assume that all of the initial spring potential energy gets transformed to gravitational potential energy.

lol of course. That gave the right answer. thanks so much for everyone's help

## 1. How do you determine the block height of a spring to 2 significant figures?

To determine the block height of a spring to 2 significant figures, you will need to use the formula h = F/k, where h is the block height, F is the force applied, and k is the spring constant. You will also need to know the force and spring constant of the spring in order to solve for the block height.

## 2. Why is it important to find the block height of a spring to 2 significant figures?

Finding the block height to 2 significant figures ensures that the measurement is accurate and precise. This is important in scientific experiments and calculations as it allows for more reliable data and results.

## 3. What are the units for block height in this scenario?

The units for block height in this scenario will depend on the units used for force and spring constant. For example, if the force is measured in Newtons and the spring constant is measured in N/m, then the block height will be measured in meters (m).

## 4. Can this formula be applied to all types of springs?

Yes, this formula can be applied to all types of springs as long as the force and spring constant are known. However, it is important to note that different types of springs may have different units for their spring constant, such as lbs/in for a compression spring or N/m for a tension spring.

## 5. Is it necessary to round the block height to 2 significant figures?

Yes, it is necessary to round the block height to 2 significant figures in order to maintain consistency and accuracy in the measurement. Rounding to 2 significant figures means that the measurement will have two numbers that are meaningful and relevant to the calculation.

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