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2sinx = cos(x-60), for 0<=x<=360

so far i expanded the cos part

2sinx = cosxcos60 + sinxsin60

as cos60 = 1/2 and sin60 = (sqrt3)/2

2sinx = (1/2)cosx + ((sqrt3)/2)sinx

sinx = cosx + sqrt3 sinx

(1-sqrt3)sinx = cosx

but here's where I'm stuck, i have 2 trig functions in one equation and therefore cannot solve.