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Solving algerbraiclly I know I'm stupid

  1. Apr 1, 2004 #1
    Solving Algerbraiclly...Nevermind!

    It seems I always try a different section of the forums just as someone is answering my out of place one.... Haha...
     
    Last edited: Apr 1, 2004
  2. jcsd
  3. Apr 1, 2004 #2

    ahrkron

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    Staff Emeritus
    Gold Member

    [tex](0.1x)^2 = (0.1)^2 \times (x)^2 = 0.01x^2[/tex]

    In general,

    [tex](ab)^2 = a^2 b^2[/tex]

    And, btw, welcome to the forums!
     
    Last edited: Apr 1, 2004
  4. Apr 1, 2004 #3
    Thanks ahrkron, and yeah you nailed my problem right on the head! Thank You!
     
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