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Solving AM = MB

  1. Oct 14, 2008 #1
    I would like to solve AM = MB where A,B,M are 3x3 matrices.

    What I came up with was to equate every entry in C to the corresponding entry in D (where C = AM and D = MB).

    You can then vectorize M (call it Mv) and figure out the 9 equations to fill a 9x9 matrix on both sides

    9x9 matrix times Mv = 9x9 matrix times Mv

    Each row on the right can be subtracted from the same row on the left, leaving

    9x9 times Mv = 0

    The problem is, I could construct this matrix easily by hand, but this seems like an obnoxious process to write in code (a couple of loops or something?) Is there a better/different way to do this so that I can use normal algebra notation to express this?

    Thanks,
    Dave
     
  2. jcsd
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