- #1

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## Main Question or Discussion Point

I'm confused by why my work is wrong:

[tex]3x^{2}+12x>0[/tex]

[tex]3x(x+4)>0[/tex]

3x>0 , x+4>0

x>0 , x>-4

However, the correct answers are: x>0 and x<-4??? Why is the sign reversed on -4? I thought you were only suppose to reverse it if you multiply or divide the equation by a negative number?

[tex]3x^{2}+12x>0[/tex]

[tex]3x(x+4)>0[/tex]

3x>0 , x+4>0

x>0 , x>-4

However, the correct answers are: x>0 and x<-4??? Why is the sign reversed on -4? I thought you were only suppose to reverse it if you multiply or divide the equation by a negative number?