- #1

logearav

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## Homework Statement

Hi Members,

I have solved an equation involving Coulomb's law in two ways and have posted the images of the same. I get two types of equations. Please help me to find where i gone wrong?

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- Thread starter logearav
- Start date

- #1

logearav

- 338

- 0

Hi Members,

I have solved an equation involving Coulomb's law in two ways and have posted the images of the same. I get two types of equations. Please help me to find where i gone wrong?

- #2

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- 2,760

I looked at your second solution where you get a quadratic equation (you almost have the solution), but you apparently don't know how to factor it to get the solution. It is an interesting problem where the instructor combined the algebra of a quadratic expression with the physics. This solution of your quadratic equation is quite simple: It factors ## (Q_1-(8.0 \cdot E-6))(Q_1+(2.0 \cdot E-6))=0 ## This gives two possible solutions for ## Q1 ##. One is positive and one is negative. When you solve for ## Q_2 ## you will see that the results are such that Q1 and Q2 are a pair of charges of two (different) positive numbers, or a pair of negative charges with the same values (with the absolute values interchanged). Please proceed to solve the equation that I factored for you, and get the results. If you have any additional questions on this one, I'd be happy to assist. ... editing...the image is a little blurred, but in your final line the first term should read ## Q_1^2 ##. (It looks like you may have written ## Q_1^3 ##, but I can't see it real clearly to tell for sure.)

Last edited:

- #3

logearav

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and for second one i get q

My question is why i get different powers for the term involving -16.

- #4

SteamKing

Staff Emeritus

Science Advisor

Homework Helper

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Both of your posted solutions appear to give the same quadratic._{1}^{2}-6*10^{-6}q_{1}-16*10^{-12}= 0

and for second one i get q_{1}^{2}- 6*10^{-6}q_{1}-16*10^{6}= 0.

My question is why i get different powers for the term involving -16.

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