- #1
koolmodee
- 51
- 0
x=[tex]\frac{1+c+a(\frac{1+c+ax}{2})}{2}[/tex]
should give x=[tex]\frac{1+c}{2-a}[/tex]
I've been trying to solve it now for like two hours. Some hints?
thank you
should give x=[tex]\frac{1+c}{2-a}[/tex]
I've been trying to solve it now for like two hours. Some hints?
thank you