Its funny.. because I got this right on a test.. but.. I'm looking back at it.. and it doesn't make sense how I figured it out...(adsbygoogle = window.adsbygoogle || []).push({});

I had to find the IC of [tex]d(\frac{x^2}{y})[/tex]

this was my work...

[tex]d(\frac{x^2}{y}) = 2xy - x^2y^2 - y^2[/tex]

[tex]d(\frac{x^2}{y}) = \frac{2xy - x^2y}{y^2}[/tex]

I'm just confused because I would of thought that it would of been something like this...

[tex]d(\frac{x^2}{y}) = 2xy^-^1 + x^2y^-^2[/tex]

hmm...?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Solving an IC

**Physics Forums | Science Articles, Homework Help, Discussion**