- #1

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## Main Question or Discussion Point

Its funny.. because I got this right on a test.. but.. I'm looking back at it.. and it doesn't make sense how I figured it out...

I had to find the IC of [tex]d(\frac{x^2}{y})[/tex]

this was my work...

[tex]d(\frac{x^2}{y}) = 2xy - x^2y^2 - y^2[/tex]

[tex]d(\frac{x^2}{y}) = \frac{2xy - x^2y}{y^2}[/tex]

I'm just confused because I would of thought that it would of been something like this...

[tex]d(\frac{x^2}{y}) = 2xy^-^1 + x^2y^-^2[/tex]

hmm...?

I had to find the IC of [tex]d(\frac{x^2}{y})[/tex]

this was my work...

[tex]d(\frac{x^2}{y}) = 2xy - x^2y^2 - y^2[/tex]

[tex]d(\frac{x^2}{y}) = \frac{2xy - x^2y}{y^2}[/tex]

I'm just confused because I would of thought that it would of been something like this...

[tex]d(\frac{x^2}{y}) = 2xy^-^1 + x^2y^-^2[/tex]

hmm...?