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kurgen88

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## Homework Statement

A solid bowling ball rolls down a hill with a height of 12.00 meters. The end of the hill has a ramp/jump which has an unknown angle above the horizontal. When the ball leaves the ramp at the unkown angle, its speed is13.09 meters per second and travels a distance of 200.0 meters.

I need to solve for the angle which the ball leaves the ramp, but the fact that the ball travels 200.0 meters seems like it is impossible. Is this a trick question? Does anyone have any suggestions on how I can solve for this?

## Homework Equations

gravity*distance=-2V^2 * sin(theta)cos(theta)

or...

-Sin(2theta) = (gravity/initial velocity^2)

...where gravity = 10.0 meters/sec^2

I have tried to solve this way but I don't think I can isolate theta from Sin(2

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