1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Solving an ODE

  1. Aug 26, 2012 #1
    1. The problem statement, all variables and given/known data
    A,B,C are real constants
    3. The attempt at a solution
    This kinda looks like a Bernoulli equation but not really.
    I thought about using an integrating factor but there is function of x on the right side.
    If I tried undetermined coefficients what would my guess function be.
  2. jcsd
  3. Aug 26, 2012 #2
    It seems like you could solve this by first manipulating to get [tex]y' + \frac{Bx-C}{A}y = 0[/tex] at which point you now have an ODE of the form [tex]y' + P(x)y = Q(x)[/tex] and there is a general way to solve such ODEs.
  4. Aug 26, 2012 #3
    where Q(x)=0 and then use an integrating factor.
  5. Aug 26, 2012 #4
    Yep, seems like that oughta work
  6. Aug 27, 2012 #5
    if you do that you get y=0.
  7. Aug 27, 2012 #6


    User Avatar
    Homework Helper

    or [tex]y' = -\frac{Bx-C}{A}y [/tex]

    which is separable. [tex]\frac{y'}{y} = -\frac{Bx-C}{A}[/tex].

  8. Aug 27, 2012 #7
    wow cant believe I missed that , thanks for the help
    ok so I would get
    [itex] ln(y)= \frac{-1}{A}(\frac{Bx^2}{2}-Cx)+F [/itex]
    F= integration constant
    then I just raise each side to e and I will have y
  9. Aug 27, 2012 #8


    User Avatar
    Homework Helper

    Exactly. It will be a bit simpler if you eliminate the minus sign in front of the parentheses,


Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook