# Solving Angles

## Homework Statement

find the values of a to 1 decimal place for the interval 0 <= a <= 360 for which

5sin (a+30) = 3

## The Attempt at a Solution

I know this is really easy but i've forgotten the method :(

somthing like

(a + 30) = arcsin(3/5)
a + 30 = 36.869...

but im not sure where to go from there.

Thanks

Last edited:

HallsofIvy
Science Advisor
Homework Helper

## Homework Statement

find the values of a to 1 decimal place for the interval 0 <= a <= 360 for which

5sin (a+30) = 3

## The Attempt at a Solution

I know this is really easy but i've forgotten the method :(

somthing like

(a + 30) = arcsin(3/5)
a + 30 = 36.869...

but im not sure where to go from there.

Thanks

How about subtracting 30 from both sides?

HallsofIvy
Science Advisor
Homework Helper

## Homework Statement

find the values of a to 1 decimal place for the interval 0 <= a <= 360 for which

5sin (a+30) = 3

## The Attempt at a Solution

I know this is really easy but i've forgotten the method :(

somthing like

(a + 30) = arcsin(3/5)
a + 30 = 36.869...

but im not sure where to go from there.

Thanks

What do you get if you subtract 30 from both sides?

a = 6.8....
so

a = 6.8, 180 - 6.869..,
a = 6.8 and 173.1...
is that my final answer?

Redbelly98
Staff Emeritus
Science Advisor
Homework Helper
Looks good, how about checking those numbers back in the original equation? Then you can be sure.

I.e., does 5sin(6.869+30) equal 3? And similarly for 173.131