# Solving Angles

## Homework Statement

find the values of a to 1 decimal place for the interval 0 <= a <= 360 for which

5sin (a+30) = 3

## The Attempt at a Solution

I know this is really easy but i've forgotten the method :(

somthing like

(a + 30) = arcsin(3/5)
a + 30 = 36.869...

but im not sure where to go from there.

Thanks

Last edited:

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HallsofIvy
Homework Helper

## Homework Statement

find the values of a to 1 decimal place for the interval 0 <= a <= 360 for which

5sin (a+30) = 3

## The Attempt at a Solution

I know this is really easy but i've forgotten the method :(

somthing like

(a + 30) = arcsin(3/5)
a + 30 = 36.869...

but im not sure where to go from there.

Thanks
How about subtracting 30 from both sides?

HallsofIvy
Homework Helper

## Homework Statement

find the values of a to 1 decimal place for the interval 0 <= a <= 360 for which

5sin (a+30) = 3

## The Attempt at a Solution

I know this is really easy but i've forgotten the method :(

somthing like

(a + 30) = arcsin(3/5)
a + 30 = 36.869...

but im not sure where to go from there.

Thanks
What do you get if you subtract 30 from both sides?

a = 6.8....
so

a = 6.8, 180 - 6.869..,
a = 6.8 and 173.1...