- #1

deryk

- 10

- 0

Hello, I am trying to solve

(z^4-2+i)(z^2+1-i)=0

With the quadratic formula:

(z^2+1-i)=0

Does a=1, b=1 & c=-1?

Thanks for your time.

IM meant to

(a) Give answers in polar form using the principal argument;

(b) Give answers in cartesian form

Cartesian is (x,y) is it not and polar is (r,theta) I am just not sure about the principal argument.

(z^4-2+i)(z^2+1-i)=0

With the quadratic formula:

(z^2+1-i)=0

Does a=1, b=1 & c=-1?

Thanks for your time.

IM meant to

(a) Give answers in polar form using the principal argument;

(b) Give answers in cartesian form

Cartesian is (x,y) is it not and polar is (r,theta) I am just not sure about the principal argument.

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