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Solving Congruences

  1. Oct 11, 2008 #1
    if we knew how to solve [tex] f(x)= 0 mod (p^{l-1}) [/tex] (1)

    could we solve then [tex] f(x)= 0 mod (p^{l}) [/tex] for integer 'l'

    the idea is, if it were easy to solve [tex] f(x)= 0 mod (p) [/tex] then we could easily find a solution to (1) but i do not know how to do it.
  2. jcsd
  3. Oct 13, 2008 #2


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    It's not even clear that
    has solutions, let alone that we can easily find them.
  4. Oct 13, 2008 #3


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    But don't just immediately click on that link! Think about the problem first. Suppose you knew that f(x) had exactly one root modulo p. (Let's say a is that root) Then isn't there a very narrow range of possibilities for a root of f(x) modulo p^2?
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