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Solving differential system with matrices

  1. Apr 9, 2012 #1
    I am solving a system X'=AX
    where A=[(1,-1,1),(0,2,-1),(0,0,1)]
    I have found my eigenvalues where Lamda = 2, and 1 w/ mult.2
    now in finding my eigenvectors when Lamda = 1 my matrix looks
    like this: [(0,1,-1),(0,0,0),(0,0,0)] and the 1st eigenvector is (0,1,1)
    and I'm pretty sure from past linear algebra class the 2nd one is (1,0,0) but I can't remember why. if in this matrix there is no x1 how come it has a value in this vector. I remember being flumoxed by this before and I just want to understand why and what I'm doing here. Thanks!
  2. jcsd
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