1. The problem statement, all variables and given/known data Instructions: For the following inequalities, determine if 0 is a number in the solution set. 1) 3x [tex]\leq[/tex] x+1 [tex]\leq[/tex] x-1 2) x(2x-1) [tex]\leq[/tex] x+7 2. Relevant equations 3. The attempt at a solution 1) LS: [tex]3x \leq x+1 [/tex] [tex]3x-1 \leq x [/tex] [tex]-1 \leq -3x [/tex] [tex]-1/-2 \geq -2x/-2[/tex] [tex]1/2 \geq x [/tex] RS: [tex]x+1 \leq x-1[/tex] [tex]0 \leq -2[/tex] I said for the right side that there are no solutions, since the inequality is not true. So I said that 0 is not included in the solution set in this inequality, based from the inequality from the left side. 2) [tex] x(2x-1) \leq x+7 [/tex] [tex] 2x^2 - x \leq x+7 [/tex] [tex] 2x^2 - 2x - 7 \leq 0 [/tex] After that I tried factoring the equation. It would work, just not with even numbers though...have some decimals on it. This is what I tried so far for both questions. Note: I looked at the wrong part of the question, that's why I changed the question, but its still the same equations.