Solving Equations

1. Mar 5, 2009

khatche4

I am given 2 equations (for a calculus problem)...
y(x2 +4)=5 and x2 +y2 -2y=0.
I know how to solve for y in terms of x for the first equation, but I am seriously stumped on how to get passed:
y2 -2y=-x2

2. Mar 5, 2009

symbolipoint

We do not see yet how the calculus aspects will be involved, but only your two equations which you wish to solve. The first equation will permit you to find y in terms of x. The second equation will allow you to find x2 in terms of y. One of these will allow you to perform a substitution which will yield an equation more easily managed and solved.

note that you seem to almost have the right idea with your line at the botton of your post. When you rectify that, you will have something to substitute.

Last edited: Mar 5, 2009
3. Mar 6, 2009

praharmitra

solving for y in the second equation is not difficult. Ever solved quadratic equations??? do you know any formula to solve a quadratic in y?? (x is constant)

or.... add one to both sides.. do u see anything familiar?