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Solving Equilibrium Constant

  1. Jun 9, 2013 #1

    Air

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    The problem statement, all variables and given/known data
    With the 5 equations, the equilibrium contants can be calculated at the bottom. (See image)
    P1.jpg

    My complication
    I am aware that [itex]X = 200[/itex] thus that value remains at that. Also, From the fourth equation [itex]K_{out}[/itex] = [itex]Cl_{out}[/itex]. But, I cannot seem to work out the values. If not simple algebra, what am I missing?
     
  2. jcsd
  3. Jun 9, 2013 #2

    Borek

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    Staff: Mentor

    Won't hurt if you would explain what is the question that you are solving, at the moment you just posted a bunch of equations describing some undefined system.
     
  4. Jun 9, 2013 #3

    Air

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    P12.jpg

    From this, finding the concentrations at equilibrium.
     
  5. Jun 9, 2013 #4

    Air

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    I understand how the equations are set up but I can't seem to solve the maths to get the equilibrium constants. Is there something I am missing? Like I said, I am aware that [itex]X = 200[/itex] thus that value remains at that. Also, From the fourth equation [itex]K_{out}[/itex] = [itex]Cl_{out}[/itex].
     
  6. Jun 9, 2013 #5

    Borek

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    Staff: Mentor

    Simple algebra.

    My bet is your problem is related to the fact you have too many equations - they are not all independent, which makes you getting 0=0 type result.
     
  7. Jun 9, 2013 #6

    epenguin

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    Homework Helper
    Gold Member

    By equilibrium constants are we to guess that the protein forms complexes we might call XCl- and XCl2 in non-coperative fashion so it is characterised by a single equilibrium constant which it is required to calculate from the data?

    I think you had better cite the entire question.
     
    Last edited: Jun 9, 2013
  8. Jun 10, 2013 #7

    Air

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    The whole question is posted in post number 3. https://www.physicsforums.com/showpost.php?p=4410136&postcount=3
     
  9. Jun 10, 2013 #8

    Borek

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    You do realize there is no problem with solving the question using your approach and the simple algebra, it is just a matter of ignoring superfluous information?
     
  10. Jun 10, 2013 #9

    Air

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    When I substitute into each other, they all just cancel out to 0=0.
     
  11. Jun 10, 2013 #10

    Borek

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    Staff: Mentor

    Which is exactly what I wrote in the post #5 - have you read it? That's because the linear equations are not independent. Ignore one of the linear ones and you will get the correct answer.
     
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