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Solving for A in Sin(A+b)

  1. Sep 23, 2010 #1
    1. The problem statement, all variables and given/known data

    given this formula, i have to solve for A

    n=sin[(A+B)/2]/sin(B/2)


    2. Relevant equations



    3. The attempt at a solution

    Heres how far I got

    2nsin(B/2) = sin(A+B) i know this can expand out to
    =sinAcosB + cosAsinB but this isnt much help. Anyone got a suggestion
     
  2. jcsd
  3. Sep 23, 2010 #2
    Made me think of the interweb

    [tex]sin(\frac{B}{2}) = sin(\frac{B}{2}) = \frac{1-cos(B)}{2}[/tex]
     
    Last edited: Sep 23, 2010
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