- #1
Rib5
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Hey, I'm having some trouble solving for the dA portion of Guss's Law for a sphere as the Gaussian surface and a point charge on the inside.
According to my book, Integral(1dA) = 4(pi)r^2
So when I try to integrate it myself I get 2(pi^2)r^2
The integral I solve is [tex]\int[/tex][tex]\int r\phi r\theta[/tex] where theta = [0,2pi] and phi = [0,pi]
Can anyone set me straight please?
According to my book, Integral(1dA) = 4(pi)r^2
So when I try to integrate it myself I get 2(pi^2)r^2
The integral I solve is [tex]\int[/tex][tex]\int r\phi r\theta[/tex] where theta = [0,2pi] and phi = [0,pi]
Can anyone set me straight please?
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