# Solving for Log Base

1. Jan 13, 2009

### Faint

1. The problem statement, all variables and given/known data

3 = Log2x 64

2. Relevant equations
N/a

3. The attempt at a solution

3 = Log2x 64
2x3 = 64
x3 = 32
x = Cubic root of 32
x = 3.1748

I'm fairly certain the answer has to be 2 b/c 2x would be equal to 4, and 43 = 64.

Anyone mind helping me on this one? Probably a really simple error.

2. Jan 13, 2009

(2x)3 not 2*x3

Hover: your logic is flawed in that it omits the log

3. Jan 13, 2009

### Faint

As Saladsamurai said, the entire (2x) term would be cubed. The resulting answer is then 256, which is too much obviously.

4. Jan 13, 2009

$(2x)^3=64\Rightarrow 2^3*x^3=64\Rightarrow 8x^3=64\Rightarrow x^3=8\Rightarrow x=2$