# Solving for theda

1. Sep 20, 2007

### mathcrzy

how do you solve for theda in the equation sin2theda=((2)(9.8))/(7.6^2).

i have figured the right side of the equation to be .339 and so im left with sin2theda on the left and i dont know how to get theda by itself.

2. Sep 20, 2007

### nicksauce

Take the arcsin of the right side, then divide by 2.

3. Sep 21, 2007

### Staff: Mentor

Do you mean $\sin^2 \theta$ (square of the sine of theta) or $\sin (2\theta)$ (sine of (two times theta))?