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Solving for theda

  1. Sep 20, 2007 #1
    how do you solve for theda in the equation sin2theda=((2)(9.8))/(7.6^2).

    i have figured the right side of the equation to be .339 and so im left with sin2theda on the left and i dont know how to get theda by itself.
     
  2. jcsd
  3. Sep 20, 2007 #2

    nicksauce

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    Homework Helper

    Take the arcsin of the right side, then divide by 2.
     
  4. Sep 21, 2007 #3

    jtbell

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    Staff: Mentor

    Do you mean [itex]\sin^2 \theta[/itex] (square of the sine of theta) or [itex]\sin (2\theta)[/itex] (sine of (two times theta))?
     
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