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Express the acceleration in terms of v_initial, v_final, and s:

that was easy.. i got

a=(v_final-v_initial)/(s/((v_initial+v_final)/2))

since F=ma

W=F*s

the question is

**Give an expression for the work in terms of m, v_initial, v_final**?

and i cant seem to eliminate the 's' because i end up getting

W=m*a(see above) *s and i cant get eliminate it? any ideas?