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a particle of mass m moving in the x direction at constant acceleration a . During a certain interval of time, the particle accelerates from v_initial to vfinal , undergoing displacement s given by s=x_final-x_initial.
Express the acceleration in terms of v_initial, v_final, and s:
that was easy.. i got
a=(v_final-v_initial)/(s/((v_initial+v_final)/2))
since F=ma
W=F*s
the question is Give an expression for the work in terms of m, v_initial, v_final ?
and i can't seem to eliminate the 's' because i end up getting
W=m*a(see above) *s and i can't get eliminate it? any ideas?
Express the acceleration in terms of v_initial, v_final, and s:
that was easy.. i got
a=(v_final-v_initial)/(s/((v_initial+v_final)/2))
since F=ma
W=F*s
the question is Give an expression for the work in terms of m, v_initial, v_final ?
and i can't seem to eliminate the 's' because i end up getting
W=m*a(see above) *s and i can't get eliminate it? any ideas?