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kalupahana

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## Homework Statement

A stone is projected vertically with a initial velocity

**u**. Another stone projected from the same position verticaly with same velocity

**u**after time

**t**. Find the velocity of both stones when they meet together & time taken to meet.

## Homework Equations

S = ut + 1/2 at

^{2}

v = u + at

V

^{2 }= u

^{2}+ 2as

## The Attempt at a Solution

Max height = u/2g

time taken reach max height = u/g

Time taken to reach first stone ground = 2u/g

So I took time taken to meet two as

t + t/2 = 3t/2

Instance velocity of bath should be equal when they meet.

So

Using v = u + at

V= u + 3gt/2

But answer is given as gt/2, I cannot reach to this

& time is given as t/2 + u/g

I can take time if the

**t**is time taken to reach the max point.

t= u/g

Then

Time = t/2 + u/g

Please help me to reach to this answer.

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