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Homework Help: Solving for x

  1. Sep 27, 2006 #1
    I have an equation on my homework that looks like this.

    [tex]\frac{x}{2}+ \frac{x}{3}+10=x [/tex]

    I have to solve for x but have no idea what the first step is. I know I'm making it more complicated than it is, but it's been awhile since I was in Algebra 1! Any ideas??
     
    Last edited: Sep 27, 2006
  2. jcsd
  3. Sep 27, 2006 #2
    [tex] \frac{x}{2} + \frac{x}{3} = \frac{3x+2x}{6} [/tex]. So you know have [tex] \frac{5x}{6} + 10 = x [/tex]. Can you take it from there? Remember:

    [tex] \frac{a}{b} + \frac{c}{d} = \frac{ad+cb}{bd} [/tex]

    [tex] \frac{5x+60}{6} = x, 5x+60 = 6x, x = 60 [/tex]
     
    Last edited: Sep 27, 2006
  4. Sep 27, 2006 #3
    1. Bring everything to a common denominator.
    (3*x)/6+(2*x)/6+60/6=6*x/6
    2. Remove the denominator as it is present in both the left side and the right side of the equation.
    3x+2x+60=6x
    3. Gather all the x on the right side of the eq.
    60=6x-3x-2x
    60=x
     
  5. Sep 27, 2006 #4
    Thanks

    Ah yes, now I remember. I knew it really wasn't that hard as long as you knew which steps to take in which order. Both of these ways of solving it helped me a lot. Thank you very much!! :smile:
     
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