# Solving for x

1. Sep 27, 2006

### GLprincess02

I have an equation on my homework that looks like this.

$$\frac{x}{2}+ \frac{x}{3}+10=x$$

I have to solve for x but have no idea what the first step is. I know I'm making it more complicated than it is, but it's been awhile since I was in Algebra 1! Any ideas??

Last edited: Sep 27, 2006
2. Sep 27, 2006

$$\frac{x}{2} + \frac{x}{3} = \frac{3x+2x}{6}$$. So you know have $$\frac{5x}{6} + 10 = x$$. Can you take it from there? Remember:

$$\frac{a}{b} + \frac{c}{d} = \frac{ad+cb}{bd}$$

$$\frac{5x+60}{6} = x, 5x+60 = 6x, x = 60$$

Last edited: Sep 27, 2006
3. Sep 27, 2006

1. Bring everything to a common denominator.
(3*x)/6+(2*x)/6+60/6=6*x/6
2. Remove the denominator as it is present in both the left side and the right side of the equation.
3x+2x+60=6x
3. Gather all the x on the right side of the eq.
60=6x-3x-2x
60=x

4. Sep 27, 2006

### GLprincess02

Thanks

Ah yes, now I remember. I knew it really wasn't that hard as long as you knew which steps to take in which order. Both of these ways of solving it helped me a lot. Thank you very much!!