1. The problem statement, all variables and given/known data Doing a DE and need to solve for y, just wondering about this particular case. 2. Relevant equations ln ((2y-1)/(y-1)) = x for y 3. The attempt at a solution Wolfram says the result is: http://www.wolframalpha.com/input/?i=solve+ln+((2y-1)/(y-1))+=+x+for+y" How/why did the y and e^x switch places? I know the first step is to exponentiate to get rid of the ln yielding (2y-1)/(y-1) = e^x, but why the heck would you just switch the y's with the e^x after that? Is it because the graph has symmetry over the y=x line? That's all I can figure. If that is the case, how can you tell this is true offhand? http://www.wolframalpha.com/input/?i=graph+y+=+(e^x-1)/(e^x-2)" http://www.wolframalpha.com/input/?i=graph+(2y-1)/(y-1)+=+e^x" Thanks!