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Solving for y

  1. Jun 17, 2011 #1
    solving for "y"

    1. The problem statement, all variables and given/known data
    Solve for y in 16y2 -24xy -300y +x2 + 400x = 0


    2. Relevant equations
    N/A


    3. The attempt at a solution
    16y2 -24xy -300y +x2 + 400x = 0
    16y2 -24xy -300y = -x2 - 400x
    y (16y - 24x - 300) = -x2 - 400x

    When I get here, I can isolate the y but not the y
     
  2. jcsd
  3. Jun 18, 2011 #2

    Mark44

    Staff: Mentor

    Re: solving for "y"

    What you are calling y and y are the same thing, so you have not isolated y.

    The equation is quadratic in y, so you can solve for y using the Quadratic Formula.
    16y2 -24xy -300y +x2 + 400x = 0
    <==> 16y2 + (-24x - 300)y + (x2 + 400x) = 0

    This is now in the form ay2 + by + c = 0. Can you take it from here?
     
  4. Jun 18, 2011 #3

    hunt_mat

    User Avatar
    Homework Helper

    Re: solving for "y"

    What mark44 is saying is that your equation is a quadratic in y, and there is a forumla for those.
     
  5. Jun 18, 2011 #4

    Mentallic

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    Homework Helper

    Re: solving for "y"

    lol :wink:
     
  6. Jun 18, 2011 #5

    hunt_mat

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    Homework Helper

    Re: solving for "y"

    Perhaps I should have read mark44's post a little more closely...
     
  7. Jun 18, 2011 #6
    Re: solving for "y"

    Thank you all for the help

    I see what I should do now, but I continue to get weird answers when I plug it into the quadratic formula. I'm sure it's just too early for me to be doing this stuff lol. I'll continue trying.

    Thank you
     
  8. Jun 18, 2011 #7

    Mark44

    Staff: Mentor

    Re: solving for "y"

    Not sure what you mean by "weird answers," but there will be two solutions for y, both involving x.
     
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