- #1
Jeff Ford
- 155
- 2
I'm trying to solve the following equation for y
[tex] 2y^2 + xy = x^2 + 3 [/tex]
So far I've gotten it down to [tex] y = \frac{x^2 + 3}{2y = x} [/tex]
Or I've tried [tex] (2y-x)(y+x) = 3 [/tex]
But I'm stuck at that. Any advice would be appreciated.
[tex] 2y^2 + xy = x^2 + 3 [/tex]
So far I've gotten it down to [tex] y = \frac{x^2 + 3}{2y = x} [/tex]
Or I've tried [tex] (2y-x)(y+x) = 3 [/tex]
But I'm stuck at that. Any advice would be appreciated.