# Solving I2 in polar form

noname1
I got this equation

5<0° = -14.14<-45° + 2.24<116.6° I2

And i solved I2 this way

I2 = -14.14<-45° / 2.24<116.6°

I2 = 8<150.29°

I want to know complex numbers is the same way as normal math or not

Mentor
I got this equation

5<0° = -14.14<-45° + 2.24<116.6° I2

And i solved I2 this way

I2 = -14.14<-45° / 2.24<116.6°

I2 = 8<150.29°

I want to know complex numbers is the same way as normal math or not

What is I2? Is it something special, or just a term multiplying the 2nd number on the righthand side (RHS) of the equation?

If the latter, I think it would be more traditional to write it as:

5<0° = -14.14<-45° + I2 * 2.24<116.6°

noname1
i2 is being multiplied, its a current in the second mesh but i just wanted to be sure if it is that way its calculated

Mentor
i2 is being multiplied, its a current in the second mesh but i just wanted to be sure if it is that way its calculated

In that case, I don't think you've solved for I2 correctly. For one thing, the LHS term disappeared?

To add the two terms on the RHS, you would convert from polar to rectangular form, and add the x and y components. Then represent the LHS in rectangular components (that part is easy), and solve for I2.

noname1
In that case, I don't think you've solved for I2 correctly. For one thing, the LHS term disappeared?

To add the two terms on the RHS, you would convert from polar to rectangular form, and add the x and y components. Then represent the LHS in rectangular components (that part is easy), and solve for I2.

what do you mean by lhs and rhs? i am kind of lost

Mentor
what do you mean by lhs and rhs? i am kind of lost

I defined the term RHS in my post #2.

noname1
I defined the term RHS in my post #2.

this is what i did, i put i2 term on left side and than the rest on the rhs and since i want I2 i divided both equations by 2.24<116.6°

5<0° = -14.14<-45° + I2 * 2.24<116.6°

5<0° + 14.14<-45° = I2 * 2.24<116.6°

(5<0° + 14.14<-45°) / 2.24<116.6° = I2

I2 = 8<150.29°

Mentor
this is what i did, i put i2 term on left side and than the rest on the rhs and since i want I2 i divided both equations by 2.24<116.6°

5<0° = -14.14<-45° + I2 * 2.24<116.6°

5<0° + 14.14<-45° = I2 * 2.24<116.6°

(5<0° + 14.14<-45°) / 2.24<116.6° = I2

I2 = 8<150.29°

How are you adding terms in polar form?

noname1
How are you adding terms in polar form?

this part

(5<0° + 14.14<-45°) / 2.24<116.6° = I2

i have my ti-89 calculating it but i just want to know if it is correct if i can calculate polar form like a normal equation

example

3x -5 = 10
3x = 15
x=5

Mentor
this part

(5<0° + 14.14<-45°) / 2.24<116.6° = I2

i have my ti-89 calculating it but i just want to know if it is correct if i can calculate polar form like a normal equation

example

3x -5 = 10
3x = 15
x=5

LOL. Your calculator is doing the conversions for you (hopefully). You might want to double check the answer the good old fashioned way, by hand, just to be sure you understand the process.