Solving in intervals

1. May 22, 2008

essaichay

Hi everyone,

Trying to revise and I came across this question:

Solve the eqn cosec^2x = (3cotx + 4)/2, giving all values of x in the interval 0 < x < 2pi in radians to two dp.

I ended up with two principal values/angles (working in degrees at the moment), which are:

tan^-1(x) = 26.6 deg. and tan^-1(x) = -63.4 deg.

i used the formula pv + 180n, and got the right answers for -63.4 deg, which are:

2.03 rad and 5.18 rad, but when I applied the same forumla to solve tan^-1(x) = 26.6 deg

Completely confused on this as I'm sure I didn't misuse the formula.

Any suggestions on this would be great!