x^2 + (1-i)x + (-6 + 2i) = 0, solve in terms of a + bi
The Attempt at a Solution
Here's what I have so far... But I could be wrong.
x = -(x-xi) +/- sqrt[ (x-xi)^2 - 4(-6 + 2i) ] / 2
x = -(x-xi) +/- sqrt[ (x^2 - 2xi + xi^2) + 24 - 8i ] / 2
I'm having trouble simplifying this part. Did I do something wrong?