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Solving in the form a+bi

  • Thread starter duki
  • Start date
  • #1
264
0

Homework Statement



x^2 + (1-i)x + (-6 + 2i) = 0, solve in terms of a + bi

Homework Equations



The Attempt at a Solution



Here's what I have so far... But I could be wrong.

x = -(x-xi) +/- sqrt[ (x-xi)^2 - 4(-6 + 2i) ] / 2

x = -(x-xi) +/- sqrt[ (x^2 - 2xi + xi^2) + 24 - 8i ] / 2

I'm having trouble simplifying this part. Did I do something wrong?
 

Answers and Replies

  • #2
200
0
Remember that x should not be on the right hand side of the equation; b is just 1-i, not (1-i)*x.
 
  • #3
264
0
Ohhhh snap. Let me try again.
 
  • #4
264
0
So now I get to

-(1 - i) +/- sqrt[ 25 - 10i + i^2 ] / 2

And again, I'm stuck on the simplification.
 
  • #5
djeitnstine
Gold Member
614
0
Check for factors, you have another quadratic under the root
 
  • #6
264
0
So I factor that to (i - 5)^2 and get:

-(1 - i) +/- (i -5) / 2...
 

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