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Solving Inequalities

  1. Jan 14, 2008 #1
    Hey..This is a question I am having difficulty in solving.
    4x[tex]\angle[/tex]2x+1[tex]\leq[/tex]3x+2

    First I removed the "1"from the centre. Then I tried eliminating the X's from both sides, but that did not work. Could someone help me with this?
     
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  3. Jan 14, 2008 #2

    Tom Mattson

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    Solve [itex]4x<2x+1[/itex] and [itex]2x+1\leq 3x+2[/itex] separately. I would express both solutions sets as intervals. Then if both inequalities must be satisfied, what would you have to do with the two solution sets you found?
     
  4. Jan 14, 2008 #3
    so when i solve the 1st part i get x is less than 0.5. And when i solve the 2nd part, i got X is greater than/ equal to -1
    so the solution set for the 2nd part is (-infi, -1}. I'm not sure about the solution set of the 1st part..
     
  5. Jan 14, 2008 #4

    Tom Mattson

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    Right.

    Wrong. If [itex]x\geq-1[/itex] then the solution set is [itex][-1,\infty)[/itex].

    But you practically have it. You already said that [itex]x<0.5[/itex]. How do you write down the interval containing all the numbers that are less than 0.5?
     
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