# Solving limit

1. Dec 13, 2009

### kira137

1. The problem statement, all variables and given/known data
Find

limit ......(1-cos(2x^2)) / (1-cos(3x^2))
x->0

2. The attempt at a solution
since the above gave me 0/0, I used l'Hopital method..
then i got

(4x)sin(2x^2) / (6x)(sin3x^2)
which gives me 0/0 again..

so I kept on using l'Hopital.. but it seemed on going forever

is there other way to solve this..?
thank you in advance

2. Dec 13, 2009

### LCKurtz

Don't keep using LH rule. Remember you know (at least you should know):

$$\lim_{x\rightarrow 0}\frac {\sin x} x = 1$$

See if you can figure out how to use that next.

3. Dec 13, 2009

### phsopher

Using LH twice doesn't give 0/0.