- #1
answerseeker
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I can't seem to find where I am going wrong on this Question. it asks to solve:
log_3 (2x+3) - log_3(X+1) = 2 where _3 is the base of 3 for log
so far i moved the log_3(x+1) to the right side of equal sign. then i moved the 2 up as an exponent:
log_3(2x+3) = log_3(x+1)^2 then i canceled the logs out and moved the 2 back down so its :
2x+3 = 2(x+1)
then distributed the 2 to the x+1 , but then the x's cancel.
i think that maybe i should have just left it as (x+1)^2 ? is that where I am going wrong? or do i actually have to divide 2x+3 by x+1 instead of moving the log_3(x+1) over?
log_3 (2x+3) - log_3(X+1) = 2 where _3 is the base of 3 for log
so far i moved the log_3(x+1) to the right side of equal sign. then i moved the 2 up as an exponent:
log_3(2x+3) = log_3(x+1)^2 then i canceled the logs out and moved the 2 back down so its :
2x+3 = 2(x+1)
then distributed the 2 to the x+1 , but then the x's cancel.
i think that maybe i should have just left it as (x+1)^2 ? is that where I am going wrong? or do i actually have to divide 2x+3 by x+1 instead of moving the log_3(x+1) over?