I cant seem to find where im going wrong on this Question. it asks to solve: log_3 (2x+3) - log_3(X+1) = 2 where _3 is the base of 3 for log so far i moved the log_3(x+1) to the right side of equal sign. then i moved the 2 up as an exponent: log_3(2x+3) = log_3(x+1)^2 then i cancelled the logs out and moved the 2 back down so its : 2x+3 = 2(x+1) then distributed the 2 to the x+1 , but then the x's cancel. i think that maybe i should have just left it as (x+1)^2 ? is that where im going wrong? or do i actually have to divide 2x+3 by x+1 instead of moving the log_3(x+1) over?