- #1

Naeem

- 194

- 0

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a) For a given speed of the ball, what angle to the horizontal q (in degrees) will yield the greatest range?

q = ° 45 *

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b) If the ball is thrown at this same angle q, what speed will produce this greatest range (8 m) ?

v = m/s *

sqrt (78.48) OK

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c) How far can he throw the ball on a planet where g1 = 19 m/s2?

xp = m *

9.81*8/19 OK

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d) What height will the ball reach on this "maximum range" trajectory? (on the planet where g1 = 19 m/s2)

hmax = m

3.91 NO

Need help with part d,

I think we need to use the formula , X = V sqrt (2H/g), if yes, what to plug in,

Pl. Help