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α(dy/dt) + y = f(t)

for the following conditions:

(a) when f(t) = H(t) where H(t) is the Heaviside step function

(b) when f(t) = δ(t) where δ(t) is the delta function

(c) when f(t) = β^(-1)e^(t/β)H(t) with β<α

My try for all 3 are as follow:

1.

α(dy/dt) + y = f(t)

2.

(dy/dt) + (1/α)y = (1/α)f(t)

3.

finding the integrating factor

μ(t) = e^(∫(1/α)dt) = e^(t/α)

4.

[e^(t/α)](dy/dt) + (1/α)[e^(t/α)]y = (1/α)[e^(t/α)]f(t)

5.

d/dt{[e^(t/α)]y}=[(e^(t/α))/α]f(t)

6.

∫d/dt{[e^(t/α)]y}dt=∫[(e^(t/α))/α]f(t)dt

7.

[e^(t/α)]y = ......

then i dont know how to continue

please help guys...thanks