- #1
ILoveBaseball
- 30
- 0
Find the area of the region enclosed by the parametric equation
[tex]x=t^3-2t[/tex]
[tex]y=9t^2[/tex]
[tex]dx/dt = 3t^2-2[/tex]
9t^2 - 1 = 0
[tex]t=\pm \sqrt {1/9}[/tex]
[tex]\int_{-1/3}^{1/3} (9t^2)*(3t^2-2) dt[/tex]
= -2/5
anyone know where i went wrong?
[tex]x=t^3-2t[/tex]
[tex]y=9t^2[/tex]
[tex]dx/dt = 3t^2-2[/tex]
9t^2 - 1 = 0
[tex]t=\pm \sqrt {1/9}[/tex]
[tex]\int_{-1/3}^{1/3} (9t^2)*(3t^2-2) dt[/tex]
= -2/5
anyone know where i went wrong?