- #1

al_201314

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This is my first post here Anyway I have problems solving this question wonder anyone could help give me some clues as to how to go about it. Here goes:

The positive integers are bracketed as follows,

(1), (2,3), (4,5,6,7), (8,9,10,11,12,13,14,15), ...

No. of integers in the rth bracket is 2^r-1. State stae first term and last term in the nth bracket. Hence, show that the sum of the terms in the first n brackets is 2^n-1[(2^n)]-1].

Thanks very much.. I have absolutely no clue..

alvin