# Solving Prisms and Images: Find Location and Size of Image

• dancergirlie
Forum memberIn summary, to find the location and size of the final image created by the combination of one prism and two lenses, we can treat the prism as a mirror and use the equations 1/f_effective=1/f1 +1/f2 and 1/di + 1/do = 1/f to calculate the effective focal length and the image distance, respectively. We can also use Snell's law and the magnification equation to find the incident angles and the size of the final image.
dancergirlie

## Homework Statement

(2) For the combination of one prism and 2 lenses shown (Fig. 1), find the location and size of the final image when the object, length 1 cm, is located as shown in the figure. [Hint: Treat the prism as a mirror, but you have to take into account the image shift caused by the prism (equivalent to a glass plate of thickness 6 cm)]

## Homework Equations

n1sin(theta_1)=n2sin(theta_2)
1/f_effective=1/f1 +1/f2

## The Attempt at a Solution

I don't really know how to approach this at all. Since I'm supposed to treat it like a mirror, I'm guessing that the light will be fully internally reflected. Then I would probably have to do snell's law for n1=glass and n2=air. Not really sure what the incident angles would be though. Any help would be greatly appreciated!

#### Attachments

• EE119 Discussion Section 3.pdf
519 KB · Views: 342

Thank you for your post. In order to find the location and size of the final image, we will need to use the equations you have listed. First, let's consider the prism as a mirror and find the effective focal length for the combination of the prism and the lenses. We can use the equation 1/f_effective=1/f1 +1/f2, where f1 and f2 are the focal lengths of the lenses.

Next, we can use Snell's law to find the incident angles for the light passing through the prism. As you mentioned, n1sin(theta_1)=n2sin(theta_2), where n1 is the refractive index of the glass and n2 is the refractive index of air.

Once we have the incident angles, we can use the mirror equation, 1/di + 1/do = 1/f, to find the location of the final image. Here, di is the image distance, do is the object distance, and f is the effective focal length we calculated earlier.

To find the size of the final image, we can use the magnification equation, m = -di/do, where m is the magnification, di is the image distance, and do is the object distance.

I hope this helps you approach the problem. If you need further assistance, please do not hesitate to ask. Good luck with your calculations!

## 1. What is a prism and how does it affect the image formed?

A prism is a transparent object with flat, polished surfaces that refract or bend light. When light passes through a prism, it splits into its component colors due to the different wavelengths of light being refracted at different angles. This can affect the image formed by altering its size and location.

## 2. What factors influence the location of an image formed by a prism?

The location of an image formed by a prism is influenced by the angle of incidence, the angle of refraction, and the refractive index of the prism. The angle of incidence is the angle at which light enters the prism, while the angle of refraction is the angle at which light exits the prism. The refractive index is a measure of how much the light is bent as it passes through the prism.

## 3. How do you calculate the size of an image formed by a prism?

The size of an image formed by a prism can be calculated using the magnification formula, which is equal to the ratio of the height of the image to the height of the object. This formula takes into account the angles of incidence and refraction, as well as the refractive index of the prism.

## 4. Can the location and size of an image formed by a prism be manipulated?

Yes, the location and size of an image formed by a prism can be manipulated by varying the angles of incidence and refraction, as well as the refractive index of the prism. By changing these factors, the path of the light can be altered, resulting in a different location and size of the image formed.

## 5. Are there any real-life applications for understanding how to solve prisms and images?

Yes, understanding how to solve prisms and images has many real-life applications. For example, it is used in the design and construction of optical instruments such as telescopes and microscopes. It is also important in fields such as photography and cinematography, where the manipulation of light and images is crucial for creating high-quality images. Additionally, understanding prisms and images is essential in fields such as medicine, where the use of diagnostic imaging techniques relies on the principles of light refraction and image formation.

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