- #1
kiwifruit
- 8
- 0
After applying force P, block B accelerates to the right at 3m/s^2
When B has velocity of 2m/s determine:
1.The velocity of B relative to A
2.The acceleration of B relative to A
3.The absolute velocity of point C
The image attached show how this works.
I worked out the total length,L to get
L = 3(Sb - Sa) + (Sd - Sa)
so if you differentiate with respect to t you get
0 = 3 d(Sb - Sa)/dt + d(Sd - Sa)/dt
then I am stuck.
or is the differential equation supposed to be
L = 3(Sb - Sd) + 4(Sd - Sa)
so differentiating would get
0 = 3 d(Sb - Sd)/dt + 4 d(Sd - Sa)/dt
because somehow Va=3/4Vb
if its the second differential equation could someone explain how to get from there to get Va and Vb?
When B has velocity of 2m/s determine:
1.The velocity of B relative to A
2.The acceleration of B relative to A
3.The absolute velocity of point C
The image attached show how this works.
I worked out the total length,L to get
L = 3(Sb - Sa) + (Sd - Sa)
so if you differentiate with respect to t you get
0 = 3 d(Sb - Sa)/dt + d(Sd - Sa)/dt
then I am stuck.
or is the differential equation supposed to be
L = 3(Sb - Sd) + 4(Sd - Sa)
so differentiating would get
0 = 3 d(Sb - Sd)/dt + 4 d(Sd - Sa)/dt
because somehow Va=3/4Vb
if its the second differential equation could someone explain how to get from there to get Va and Vb?