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Solving Quad Trig Equations

  1. Nov 30, 2016 #1
    1. The problem statement, all variables and given/known data
    Solve cotxcsc2x=2cotx

    2. Relevant equations


    3. The attempt at a solution
    cotx(csc2-2)

    cotx = 0
    x = no solution

    x = sin-1(1/√2)

    or

    x = sin-1(-1/√2)

    I come up with the solutions x = { π/4, 3π/4, 5π/4, 7π/4}

    However the solutions are telling me that x can also be equal to π/2 and 3π/2 although I have no idea how this could be?
     
  2. jcsd
  3. Nov 30, 2016 #2
    This is wrong. What is the value of ##\cot(\pi/2)##?
     
  4. Nov 30, 2016 #3

    Ray Vickson

    User Avatar
    Science Advisor
    Homework Helper

    Your understanding of the function ##\cot x## is faulty; plot the graph ##y = \cot x## for ##0 \leq x \leq 2 \pi## to see what happens at various values of ##x##.
     
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