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**[SOLVED] Solving quadratic**

**1. Homework Statement**

1a) Solve

*f(x) = x^2- 4x+m*in the form

*f(x) = (x-a)^2+ b*

1b) What is the smallest value

*f(x)*can have?

**3. The Attempt at a Solution**

1a) Seems simple enough. I set

*f(x)*to 0 and used the completing the square method to solve. Ended up with

*f(x)=(x-2)^2+ m-4*.

I don’t know how to approach 1b) though. I’m assuming I’ve made a mistake somewhere – there is no smallest value

*f(x)*can have without knowing the value of

*m*. Is there a way to find m that I haven't picked up on, or would the answer just be

*m*- 4?

Thanks for any advice

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