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1. The problem statement, all variables and given/known data

1a) Solvef(x) = x^2- 4x+min the formf(x) = (x-a)^2+ b

1b) What is the smallest valuef(x)can have?

3. The attempt at a solution

1a) Seems simple enough. I setf(x)to 0 and used the completing the square method to solve. Ended up withf(x)=(x-2)^2+ m-4.

I don’t know how to approach 1b) though. I’m assuming I’ve made a mistake somewhere – there is no smallest valuef(x)can have without knowing the value ofm. Is there a way to find m that I haven't picked up on, or would the answer just bem- 4?

Thanks for any advice

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# Homework Help: Solving quadratic

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