# Solving sin(x + (pi/6))

OK, I worked through an assignment wanting me to rewrite formulas. However two problems are driving me crazy.

sin(x + (pi/6))
I get (sqrt(3)/2)sinX + (1/2)cosX
not really too simplified.

(sin^2(2x))(cos^2(2x))
((1-cos4x)/2) ((1+cos4x)/2)
(1-cos^2(4x))(1/4)
[((2/2)-((1+cos8x)/2)](1/4)
((1+cos8x)/4)(1/4)
(1 + cos8x)(1/16)
//When I plug numbers in I do not get a valid solution for the original equation so I messed up somewhere.

Any guidance is appreciated. Thank you for your time and knowledge. Also, congratulations this site has grown a lot since my old days of getting on about everyday. Job got in the way and all.

dextercioby
Homework Helper
The first one cannot be simplified indeed...

The second is
$$\sin^{2}2x\cos^{2}2x$$

,or i didn't understant it??

HINT:
Use
$$\sin 2u=2\sin u\cos u$$

Daniel.