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Jodi
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Hi; Could someone please help me with this question: By what fraction does the mass of an H atom decrease when it makes an n=7 to n=5 transition? How would I go about this question? Thank you.
The Bohr Model of Atom is a model proposed by Danish physicist Niels Bohr in 1913 to explain the structure of an atom. It states that electrons orbit around the nucleus in specific energy levels or shells, with the closest shell having the lowest energy and the outermost shell having the highest energy.
The transition from n=7 to n=5 in the Bohr Model of Atom represents the movement of an electron from a higher energy level to a lower energy level. This transition results in the emission of electromagnetic radiation in the form of a photon.
To solve the Bohr Model of Atom for the transition from n=7 to n=5, you need to use the formula ΔE = -Rhc(1/n_{final}^{2} - 1/n_{initial}^{2}), where ΔE is the change in energy, R is the Rydberg constant, h is Planck's constant, and c is the speed of light. Plug in the values of n=7 and n=5 to calculate the change in energy.
The transition from n=7 to n=5 in the Bohr Model of Atom is influenced by the energy difference between the two levels, the charge of the nucleus, and the mass of the electron. The energy difference between the levels determines the wavelength of the emitted photon, while the charge of the nucleus and the mass of the electron affect the speed and energy of the electron.
The Bohr Model of Atom explains the stability of atoms by stating that electrons can only exist in certain energy levels or shells around the nucleus. When the electrons are in their lowest possible energy state, the atom is considered stable. Any excess energy is emitted in the form of a photon, resulting in a stable configuration.