- #1
kennis2
- 8
- 0
i can't resolve this integral
2x^3-2x^2+1/x^2-x-2?
2x^3-2x^2+1/x^2-x-2?
p53ud0 dr34m5 said:[tex]\frac{2x^3-2x^2+1}{x^2-x-2}=2x+\frac{2x+1}{2x^3-2x^2+1}[/tex]
This is correct.[itex]\frac{2x^3-2x^2+1}{x^2-x-2}[/itex]=[itex]2x+\frac{4x+1}{x^2-x-2}[/itex]
An integral is a mathematical concept used to calculate the area under a curve or the accumulation of a quantity over a given interval. It is the inverse operation of differentiation and is denoted by the symbol ∫.
To solve an integral, you need to find the antiderivative of the given function. This can be done using integration techniques such as substitution, integration by parts, or partial fractions. Once the antiderivative is found, you can then evaluate the integral using the limits of integration.
A definite integral has specific limits of integration and gives a numerical value as the result. An indefinite integral does not have limits of integration and gives a function as the result. Definite integrals are used to calculate areas or accumulated quantities, while indefinite integrals are used to find a general function that satisfies a given derivative.
The order of operations for solving an integral is the same as for any mathematical expression: perform any operations inside parentheses, evaluate exponents, multiply and divide from left to right, and finally add and subtract from left to right.
You can check your solution to an integral by taking the derivative of your antiderivative and seeing if it matches the original function. If it does, then your solution is correct. You can also use online integral calculators or check your answer using a graphing calculator.