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Solving turning points

  1. Dec 29, 2014 #1
    calculus 001.jpg I'm wondering if I'm right or wrong. question is Apply differentiation to determine the co-ordinates of the turning points on the graph Y=X3-6X2+9x
    and finf max and min turning points
  2. jcsd
  3. Dec 29, 2014 #2


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    When you are solving the equation x2 - 4x + 3 = 0, you made a silly mistake.

    This equation has two factors, namely (x - 3) and (x - 1). Re-writing x2 - 4x + 3 = (x - 3)(x - 1) = 0. By setting each factor equal to zero independently, you can make the equation true; thus x - 3 = 0 or x - 1 = 0. The solutions you have, x = -3 and x = -1, are incorrect.
  4. Dec 29, 2014 #3
    Ok I did have trouble they're , i'm a long time away from this type of stuff and trying to remember from 25 years ago. Where should I go fro here so?
  5. Dec 29, 2014 #4


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    Correct the solutions you have and work from there. All of your work past this point must be checked again using the correct solutions.
  6. Dec 29, 2014 #5
    I used quadratic formula and got x=1,x=3
    sub in x=3

    sub in x=1



    X=1, 6(1)-12=-6
    X=3, 6(3)-12=6
    Last edited: Dec 29, 2014
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